以下是一个示例代码，演示了如何按两个嵌套值过滤对象：

def filter_objects(objects, key1, value1, key2, value2):
    filtered_objects = []
    for obj in objects:
        if key1 in obj and key2 in obj:
            if obj[key1] == value1 and obj[key2] == value2:
                filtered_objects.append(obj)
    return filtered_objects

# 示例数据
objects = [
    {"name": "Alice", "age": 25, "gender": "female"},
    {"name": "Bob", "age": 30, "gender": "male"},
    {"name": "Charlie", "age": 35, "gender": "male"},
    {"name": "Alice", "age": 28, "gender": "female"},
    {"name": "David", "age": 30, "gender": "male"}
]

# 按两个嵌套值过滤对象
filtered_objects = filter_objects(objects, "name", "Alice", "age", 25)
print(filtered_objects)

输出结果：

[{'name': 'Alice', 'age': 25, 'gender': 'female'}]

在上述示例中，filter_objects 函数接受一个对象列表 objects，以及两个键值对 key1, value1 和 key2, value2。它遍历每个对象，检查是否存在两个指定的键，然后比较键值对是否与给定的值匹配。如果匹配，将对象添加到 filtered_objects 列表中。最后，返回过滤后的对象列表。

在示例数据中，我们按照姓名为 "Alice" 和年龄为 25 过滤对象，结果只有一个对象满足条件，即 {'name': 'Alice', 'age': 25, 'gender': 'female'}。