BigQuery中使用递归方式进行相乘和求和操作，可以使用WITH RECURSIVE语句实现。下面是一个示例代码，首先定义一个初始值n并计算递归步数，然后进行递归计算直到达到步数上限。递归的基本思路是，在每次递归中将上一个迭代的结果传递给下一个迭代。

WITH RECURSIVE numbers AS ( SELECT 1 AS num UNION ALL SELECT num + 1 FROM numbers WHERE num < 10 ), -- 计算递归步数 stats AS ( SELECT 5 AS step, 1 AS num ), -- 递归计算乘积 multiply AS ( SELECT 1 AS result, step FROM stats UNION ALL SELECT result * num, step - 1 FROM multiply JOIN numbers ON numbers.num <= 2 JOIN stats ON stats.step = multiply.step ), -- 递归计算总和 sum AS ( SELECT 0 AS result, step FROM stats UNION ALL SELECT result + result_next, step FROM ( SELECT result_next, step - 1 FROM ( SELECT SUM(result) OVER (PARTITION BY step) AS result_next, step FROM multiply JOIN stats ON stats.step = multiply.step ) WHERE step > 0 ) JOIN sum ON sum.step = step ) SELECT result FROM sum WHERE step = 0;

此代码将计算乘积2 * 1 * 1 = 2和总和2 + 1 + 1 = 4。使用类似的方法，可以对更大的数字和更复杂的表达式进行乘积和求和。