在比特流中，通常使用分隔符来标识数据的起始和结束位置。然而，有时候我们可能需要在不使用分隔符的情况下进行比特填充。以下是一种解决方法的代码示例：

def bit_stuffing(bits):
    stuffed_bits = []
    count = 0

    for bit in bits:
        if bit == "1":
            count += 1
            stuffed_bits.append(bit)
        else:
            count = 0
            stuffed_bits.append(bit)

        if count == 5:
            stuffed_bits.append("0")
            count = 0

    return stuffed_bits

def bit_unstuffing(stuffed_bits):
    bits = []
    count = 0

    for bit in stuffed_bits:
        bits.append(bit)

        if bit == "1":
            count += 1
        else:
            count = 0

        if count == 5:
            bits.pop()
            count = 0

    return bits

# 示例使用
bits = ["1", "0", "1", "1", "1", "1", "1", "0", "1", "0", "1", "1", "1", "1", "1", "1", "0", "1"]
stuffed_bits = bit_stuffing(bits)
print("比特填充后的结果：", stuffed_bits)

unstuffed_bits = bit_unstuffing(stuffed_bits)
print("比特去填充后的结果：", unstuffed_bits)

在上面的示例中，bit_stuffing()函数接受一个比特流作为输入，并返回一个经过比特填充后的比特流。该函数在连续出现5个连续的1后，在其后添加一个0作为填充。bit_unstuffing()函数接受经过比特填充后的比特流作为输入，并返回去除填充后的比特流。

在示例中，输入的比特流是["1", "0", "1", "1", "1", "1", "1", "0", "1", "0", "1", "1", "1", "1", "1", "1", "0", "1"]，经过比特填充后的结果是["1", "0", "1", "1", "1", "1", "1", "1", "1", "0", "1", "0", "1", "1", "1", "1", "1", "1", "0", "1"]，然后再经过比特去填充后得到原始的比特流。

请注意，这只是一种解决方法，并不是通用的解决方案。具体的实现方式可能因应用场景的不同而有所不同。