以下是一个按组计算连续天数的示例解决方法：

def calculate_consecutive_days(date_list):
    consecutive_groups = []
    current_group = []

    for i, date in enumerate(date_list):
        if i == 0 or (date - date_list[i-1]).days == 1:
            current_group.append(date)
        else:
            consecutive_groups.append(current_group)
            current_group = [date]

    consecutive_groups.append(current_group)

    for group in consecutive_groups:
        print(f"Group: {group}, Consecutive Days: {len(group)}")


# 测试数据
dates = [datetime.date(2022, 1, 1), datetime.date(2022, 1, 2), datetime.date(2022, 1, 3),
         datetime.date(2022, 1, 5), datetime.date(2022, 1, 6), datetime.date(2022, 1, 9),
         datetime.date(2022, 1, 10), datetime.date(2022, 1, 11)]

calculate_consecutive_days(dates)

该示例使用了Python中的datetime模块来表示日期。calculate_consecutive_days函数接受一个日期列表作为参数，并按照连续的天数将日期分组。然后，对每个分组计算连续的天数并打印输出。

示例输出：

Group: [datetime.date(2022, 1, 1), datetime.date(2022, 1, 2), datetime.date(2022, 1, 3)], Consecutive Days: 3
Group: [datetime.date(2022, 1, 5), datetime.date(2022, 1, 6)], Consecutive Days: 2
Group: [datetime.date(2022, 1, 9), datetime.date(2022, 1, 10), datetime.date(2022, 1, 11)], Consecutive Days: 3