以下是一个示例代码，用于按组别计算向量中的开关数量：

def count_switches_by_group(vector):
    switch_count = []
    current_switch = None
    current_count = 0

    for element in vector:
        if element == current_switch:
            current_count += 1
        else:
            if current_switch is not None:
                switch_count.append((current_switch, current_count))
            current_switch = element
            current_count = 1

    if current_switch is not None:
        switch_count.append((current_switch, current_count))

    return switch_count


# 测试示例
vector = [1, 1, 0, 0, 1, 1, 1, 0, 1, 0, 0, 0, 0, 1, 0]
switch_count = count_switches_by_group(vector)
print(switch_count)

输出结果为：

[(1, 2), (0, 2), (1, 3), (0, 1), (1, 1), (0, 4), (1, 1), (0, 1)]

解释：向量中以相同元素为一组，计算每个组中开关的数量。结果以元组列表的形式返回，每个元组包含开关的值和该组中开关的数量。以上示例中，开关值为1的组有2个开关，开关值为0的组有2个开关，开关值为1的组有3个开关，以此类推。